21x^2+44x-32=0

Solution for 21x^2+44x-32=0 equation:

21x^2+44x-32=0

a = 21; b = 44; c = -32;
Δ = b2-4ac
Δ = 442-4·21·(-32)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-68}{2*21}=\frac{-112}{42}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+68}{2*21}=\frac{24}{42}
=4/7
$